About the problem
Suppose that \(n\) people are voting in an election with \(m\) candidates. A Condorcet winning set is a set \(W\) of candidates such that for every candidate \(y\) not in \(W\), at most half of the voters prefer candidate \(y\) to every candidate in \(W\).
This problem asks for an instance of an election in which every Condorcet winning set has size at least four. Charikar et al showed in 2025 that there always exists a Condorcet winning set of size at most six, and in 2026 Song, Nguyen, and Lin showed that there always exists a Condorcet winning set of size at most five. On the other end, there are examples with no Condorcet winning set of size two.
This problem aims to shorten the gap between the known upper and lower bounds. Charikar et al conjecture that there is always a Condorcet winning set of size at most three, so a solution to this problem would disprove that conjecture. The main risk with this problem is that the conjecture is true, and that there are no examples where a Condorcet winning set must have size at least four.
Condorcet winning sets are named for a famous paradox in voting theory, Condorcet’s paradox.
Prompt
# Condorcet Winning Sets of Size at Least Four
## Setup
An election consists of n voters and m candidates (labelled 1, 2, ..., m). Each
voter submits a strict ranking of all m candidates (a permutation), from most
preferred to least preferred.
Given a committee (a subset S of candidates) and an alternative candidate c not
in S, say that c "overthrows" S if at least half of the voters rank c above
every member of S. Formally, c overthrows S when
#{ voters v : v ranks c higher than every member of S } >= n / 2.
A committee S is a *Condorcet winning set* (CWS) if no alternative candidate
overthrows it -- that is, for every c not in S, strictly fewer than half of the
voters prefer c to the whole committee.
(Equivalently: S is a CWS iff for every candidate c not in S, a strict majority
of voters rank at least one member of S above c. This is the definition of
Elkind, Lang & Saffidine, and the "1/2-undominated" notion of Charikar et al.,
"Six Candidates Suffice to Win a Voter Majority".)
Note that any superset of a Condorcet winning set is again a Condorcet winning
set, so the relevant quantity is the size of the *smallest* CWS. The full
candidate set is always a CWS, so a smallest CWS always exists.
## Your task
Construct an election in which **every Condorcet winning set has size at least
four** -- i.e. there is no Condorcet winning set of size 3 (and hence, by upward
closure, none of size 1 or 2 either).
You choose n (the number of voters) and m >= 4 (the number of candidates).
## Submission format
Write your answer to a file as the n-by-m matrix of rankings, in plain text: n
lines, each with m whitespace-separated integers. Each of the n rows is one
voter's ranking -- the m candidate labels (1 .. m) in order from most preferred
to least preferred -- and must be a permutation of 1 .. m. Submit that file's
path using the submit tool.
Example (n = 3 voters, m = 4 candidates):
3 1 4 2
1 2 3 4
4 2 1 3
Here the first voter prefers candidate 3 > 1 > 4 > 2.
The verifier will check every 3-candidate committee and accept your submission
only if each one is overthrown by some alternative (so no size-3 Condorcet
winning set exists).